Perimeter Of A Hexagon Formula

Polygon is nothing just a closed effigy(end to terminate connected) fabricated up of more than 2 line segments on a 2-dimensional plane. A polygon is created by using direct-line segments that are end to end connected with each other, and these line segments are known as sides of the polygon and the point is known as the vertex of the polygon.

Hexagon in a two-dimensional airplane is an object that has 6 angles and half dozen sides. In a hexagon all the sides and angles are equal. The total of the internal angles of whatever hexagon is 720°. A regular hexagon has 6 rotational symmetries and 6 reflection symmetries. All internal angles are 120°.

We can ascertain perimeter equally the sum of the length of all six sides.

Perimeter = 6*southward

where, s is the side of the hexagon.

Derivation:

Nosotros know that there are six sides and all those are equal.

Consider the side as 'southward'. And then sum of vi sides is s + south + southward + s + s + s

So perimeter is 6s

Sample Problems

Question 1: Find the perimeter of the regular hexagon with ane side 2 cm.

Solution:

Given that, length of one side = 2cm

then perimeter = 6*s

substitute s = 2

=> 6*2 = 12 cm

Therefore the perimeter of the regular hexagon with one side 2 cm is 12 cm.

Question 2: Observe the perimeter of the regular hexagon with one side 10 cm.

Solution:

Given that, length of 1 side = 10cm

and so perimeter = 6*southward

substitute s = 10

=> 6*10 = 60 cm

Therefore the perimeter of the regular hexagon with ane side 10 cm is lx cm.

Question 3: One side of the pencil which is in hexagonal shape is four cm. what is the perimeter of the pencil?

Solution:

Given that, length of one side  of pencil = 4 cm

so perimeter = 6*s

substitute s = 4

=> half dozen*iv = 24 cm

Therefore the perimeter of the pencil with i side four cm is 24 cm.

Question four: There are iv nuts with each side as 2 cm and eight bolts with 3 cm as each side. Detect the perimeters of all nuts and bolts.

Solution:

We know that basics and bolts are hexagonal shape. so

In that location are four nuts with each side every bit 2 cm

each nut perimeter is six*due south => 6 * ii = 12 cm

And so , Perimeter of all nuts  is four * 12 = 48 cm

In that location are 8 bolts with each side as 3 cm

each commodities perimeter is 6*southward => 6 * three = eighteen cm

So, Perimeter  of  all bolts  is viii * 18 = 144 cm

Perimeters of all nuts and bolts is 48 cm and 144 cm

Question 5: 1 side is 12 cm long in a hexagon. Notice the length of the remaining four sides and discover the perimeter.

Solution

We know that,

Sides are equal in hexagon. So all sides are 12 cm

Hence perimeter is six*s => 6*12 = 72 cm

Therefore the length of remaining four sides are 12 cm each and the perimeter is 72 cm.

Perimeter Of A Hexagon Formula,

Source: https://www.geeksforgeeks.org/perimeter-of-hexagon-formula/

Posted by: morganhishe1987.blogspot.com

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